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25^x-3=(1/125)^x+2
We move all terms to the left:
25^x-3-((1/125)^x+2)=0
Domain of the equation: 125)^x+2)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
25^x-((+1/125)^x+2)-3=0
We multiply all the terms by the denominator
25^x*125)^x+2)-((-3*125)^x+2)+1=0
We add all the numbers together, and all the variables
25^x*125)^x+2)-((-375)^x+2)+1=0
Wy multiply elements
3125x^2-375)^x+2)+1=0
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